Presentation ~ above theme: "We require to discover out the surface ar area that the earth (SE) and the area the the widest part of the soccer ball (WAS). We’re no finding out the surface ar area."— Presentation transcript:
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2 We need to find out the surface area that the earth (SE) and also the area that the widest part of the soccer round (WAS). We’re not finding the end the surface area the the football ball because we’re not going to have the ability to stretch that apart to cover the earth. We usage WAS time the Avogadro"s number and also use the to division the SE. Climate we usage that number and times that by the diameter of the football to find out come what depth would certainly it cover.
3 Diameter: 22.2 cm surface ar Area the the widest part: A = πr 2 A = 3.14 x (22.2 cm / 2) 2 A = 386.88 cm 2 surface Area: 5.1 x 10 8 kilometres 2 or 5.1 x 10 18 centimeter 2 process Area the a mole of soccer sphere = SA of round x 1 mole =386.88cm 2 x 6.022 x 10 23 = 2.3 x 10 26 cm 2 number of times extending the planet = SA the 1 mole of soccer round ÷ SA of planet =2.3 x 10 26 ÷ 5.1 x 10 18 = 4.51 x 10 7 Depth it would certainly cover come = # of times it would certainly cover the planet x football ball’s Diameter = 4.51 x 10 7 x 22.2 cm = 1.001 x 10 9 cm Area of a Circle: πr 2 km 2 to centimeter 2 = 10 x 10 9
4 A mole of soccer balls would cover the surface of the earth to a depth that 1.001 x 10 9 cm or 10012 kilometres
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SURFACE AREA Prisms and Cylinders section 6-2. Prism A polyhedron through two congruent parallel bases called by the shape of the bases The other faces are.
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