As at t=0 the amplitude is 5 cm, so the simple harmonic motion will be in cosine form. As in case of sine function, the value of function at x=0 is 0.

*

We know that, in the function

*

period is
*
,horizontal shift or phase shift is c,amplitude is a,vertical shift is d.

As in this case the amplitude is given to be 5, hence

*

Also the period is given as 4, so

*

*

As nothing is given about the horizontal and vertical shift, so putting

*
, the function becomes,

*

or

*

As in x axis time is taken as t and in y axis distance is taken as d, so the function becomes,

*




You are watching: Find a model for simple harmonic motion if the position at t=0 is 0 the amplitude is 5 centimeters


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Elan Coil <88>10 months ago
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It would be b bc if you do all of ur steps
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