As at t=0 the amplitude is 5 cm, so the simple harmonic motion will be in cosine form. As in case of sine function, the value of function at x=0 is 0. We know that, in the function period is ,horizontal shift or phase shift is c,amplitude is a,vertical shift is d.

As in this case the amplitude is given to be 5, hence Also the period is given as 4, so  As nothing is given about the horizontal and vertical shift, so putting , the function becomes, or As in x axis time is taken as t and in y axis distance is taken as d, so the function becomes, You are watching: Find a model for simple harmonic motion if the position at t=0 is 0 the amplitude is 5 centimeters

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Elan Coil <88>10 months ago
5 0
It would be b bc if you do all of ur steps
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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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