a. For two capacitors in collection the tantamount capacitance is 6 × 12/6 + 12 = 4 μFb. The capacitors are totally charged so current flows through the resistors but not the capacitors. RT = 30 Ω and also I = V/R = 0.2 Ac. The potential difference in between A and also B is the voltage across the 20 Ω resistor. V = IR = 4 Vd. The capacitors in series store the very same charge together a single 4 μF capacitor. Q = CV = 4 μF4 V = 16 μCe. Stays the same. No current is flow from A to ns to B therefore breaking the circuit at allude P does not influence the current in the external loop and therefore will certainly not affect the potential difference between A and also B.

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